I stumbled on this nice little puzzle the other day.
I'll link to the source tomorrow when sharing the answer. Until then, have fun :)
Find all the possible ways, if any exist, to fill in the three blanks to make all three statements true.
Previous iteration: #726159 (partial proof for special case in #728029)
Here a link to a link to the answers: #731084
If you allow words instead of numbers as solutions: odd, irrational, and odd.
Even better than what Randall Munroe had in mind (#731084).
Do the
1,2, and3that label each panel count?I hadn't thought of that. That way the solution could be something else. Let's give it a try!
⣠1 = a
⣠2 = b
⣠3 = c
a = b + c + 5
b = ā(ab3)
c = min(a, b , 1)
That's up to you to decide š
There is a unique positive integer solution, assuming we include the panel identification numbers.
x3ā=1
x1ā=6+x2ā
x2ā=3x1āā
Solving it gives:
x1ā=12,x2ā=6,x3ā=1
:)
Trivial solutions are solutions too ;)
Panel 1: 1.618
Panel 2: 1.272
Panel 3: 1
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